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-2x^2-22x-56=0
a = -2; b = -22; c = -56;
Δ = b2-4ac
Δ = -222-4·(-2)·(-56)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-6}{2*-2}=\frac{16}{-4} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+6}{2*-2}=\frac{28}{-4} =-7 $
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